ZADATAK: Vreme je za uobičajeno prolećno spremanje. Dva standardna seta pentomina treba "spakovati" tako da u svakoj od 12 "fioka" (površine obeležene debljom linijom - u primeru ih ima 4) budu dva ista pentomina. Figure se mogu rotirati i reflektovati, ali se ne smeju preklapati niti dodirivati, osim dijagonalno, bez obzira da li su u istoj ili različitim fiokama.
OBRAČUN: Rezultat se obračunava posebno za svaku "fioku", a ukupan rezultat optimizacije je zbir poena u svim fiokama.
Vrednost svakog pojedinačnog polja u fiokama označena je u uglu, brojevima od 1 do 9, a vrednost svakog pentomina odgovara zbiru brojeva u poljima koja on zauzima. Razlika između vrednosti dva pentomina u istoj fioci, predstavlja rezultat te fioke. UKOLIKO DVA PENTOMINA U ISTOJ FIOCI IMAJU ISTU VREDNOST (kao pentomino "I" u primeru) ONDA JE REZULTAT TE FIOKE JEDNAK ZBIRU OVIH VREDNOSTI!
Za rešavanje optimizacije biće postavljena on-line mreža, u koju svaki pentomino treba ucrtati odgovarajućim slovom, a pored "radne mreže" zadatka biće postavljena excel tabela za poluautomatski obračun rezultata. Potrebno je samo izračunati i upisati vrednosti svih pentomina (zbir brojeva unutar svakog pojedinačnog pentomina).
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INSTRUCTIONS: It's time for spring cleaning. Two standard pentomino sets should be "packed" in a way that every of 12 "drawer" (bordered areas - 4 in example) should have two same pentominoes. Pentominoes can be rotated and mirrored, but must not overlap or touch by side each other, no matter if their position is in same or different drawer.
SCORE CALCULATION: You need to calculate your score separately for every "drawer", and your final score is sum of every single drawer.
The value of every single cell is specified in the corner, numbered from 1 to 9, and each pentomino's value corresponds to the sum of the values in a cells occupied by every single pentomino. The difference between two pentomino's values represents result of the drawer. IF TWO PENTOMINOES FROM SAME DRAWER HAVE SAME VALUE (pentominoes "I" in example), THE RESULT OF THAT DRAWER IS EQUAL TO THE SUM OF THESE VALUES!
Online grid will be uploaded for optimization solving. You should mark each pentomino part with corresponding letter, and next to the "working grid", will be set up excel table for semi-automatic calculation of results. You only need to calculate and write the value of all pentominoes (sum of the numbers within each pentomino).
Konačan rezultat optimizacije treba upisati u predviđena polja na samom zadatku, zatim snimiti rešenje (taster 'save'), a plavi link koji se pojavi iznad mreže iskopirati i poslati u e-mail poruci.
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Enter the final result of optimization in the marked fields of the puzzled, then save the solution (the button 'save'), and send the blue link that appears above the grid by e-mail message.********************************************************************************
Zahvaljujem Giši na pomoći oko tabele i prevoda
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Naslov: APRILSKA OPTIMIZACIJA 
Pon 11 Apr 2011 - 0:03
I always liked dealing with pentominos and this task includes so many opprtunities to increase our points (it is amazing by this way). I also think that semi-automatic result calculation is not a big handicap for this task. I'm saying this because it is quite easy to transfer the given data with pdf to excel and work on it. I prefer working with excel to solving by hand in such tasks. And in this task we are not voting for rating but I will definitely vote for complete rating 
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. Nadam se da poluautomatski obračun neće odvratiti potencijalne rešavače i da će se dosadašnji takmičari odazvati i ovog puta.
